2. The force of static friction of your bicycle tires against the driveway is 4.5 N . Your bike has a weight of 12 N . What is the coefficient of static friction? 3. What.is the coefficient of kinetic friction for a pulley system that uses 15 N of force to lift a load with a weight of 40 N ? 4. If the coefficient of kinetic friction is 0.23 for a box sliding across your lab table and the box weighs 7.1 N, what is the force of kinetic friction? 5. The force of static friction of your friend's bicycle tires against the driveway is 5.5 N. Your bike has a weight of 12 N. What is the coefficient of static friction? 6. What is the coefficient of kinetic friction for a pulley system that uses 20 N of force to lift a load with a weight of 50 N ?

Certainly! Let's tackle each of your physics problems one by one. --- ### **Problem 2** **The force of static friction of your bicycle tires against the driveway is 4.5 N. Your bike has a weight of 12 N. What is the coefficient of static friction?** **Solution:** The coefficient of static friction (μₛ) is calculated using the formula: \[ \mu_s = \frac{F_s}{N} \] Where: - \( F_s \) = Force of static friction = 4.5 N - \( N \) = Normal force (for a flat surface, this equals the weight) = 12 N \[ \mu_s = \frac{4.5\, \text{N}}{12\, \text{N}} = 0.375 \] **Answer:** The coefficient of static friction is **0.375**. --- ### **Problem 3** **What is the coefficient of kinetic friction for a pulley system that uses 15 N of force to lift a load with a weight of 40 N?** **Solution:** Assuming the pulley system's only opposing force is due to kinetic friction, the coefficient of kinetic friction (μₖ) can be found using: \[ \mu_k = \frac{F}{W} \] Where: - \( F \) = Force applied = 15 N - \( W \) = Weight of the load = 40 N \[ \mu_k = \frac{15\, \text{N}}{40\, \text{N}} = 0.375 \] **Answer:** The coefficient of kinetic friction is **0.375**. --- ### **Problem 4** **If the coefficient of kinetic friction is 0.23 for a box sliding across your lab table and the box weighs 7.1 N, what is the force of kinetic friction?** **Solution:** The force of kinetic friction (Fₖ) is calculated using: \[ F_k = \mu_k \times N \] Where: - \( \mu_k \) = Coefficient of kinetic friction = 0.23 - \( N \) = Normal force (equals the weight) = 7.1 N \[ F_k = 0.23 \times 7.1\, \text{N} \approx 1.633\, \text{N} \] **Answer:** The force of kinetic friction is approximately **1.63 N**. --- ### **Problem 5** **The force of static friction of your friend's bicycle tires against the driveway is 5.5 N. Your bike has a weight of 12 N. What is the coefficient of static friction?** **Solution:** Using the formula for the coefficient of static friction: \[ \mu_s = \frac{F_s}{N} \] Where: - \( F_s \) = Force of static friction = 5.5 N - \( N \) = Normal force = 12 N \[ \mu_s = \frac{5.5\, \text{N}}{12\, \text{N}} \approx 0.4583 \] **Answer:** The coefficient of static friction is approximately **0.458**. --- ### **Problem 6** **What is the coefficient of kinetic friction for a pulley system that uses 20 N of force to lift a load with a weight of 50 N?** **Solution:** Assuming the only opposing force is kinetic friction, the coefficient of kinetic friction (μₖ) can be determined by: \[ \mu_k = \frac{F}{W} \] Where: - \( F \) = Force applied = 20 N - \( W \) = Weight of the load = 50 N \[ \mu_k = \frac{20\, \text{N}}{50\, \text{N}} = 0.4 \] **Answer:** The coefficient of kinetic friction is **0.4**. --- If you have any more questions or need further clarification on these problems, feel free to ask!