Find an ordered pair \( (x, y) \) that is a solution to the equation. \( \begin{array}{l}6 x+y=7 \\ (x, y)=(\square, \square)\end{array} \)

To find an ordered pair \( (x, y) \) that is a solution to the equation \( 6x + y = 7 \), we can express \( y \) in terms of \( x \) and then choose a value for \( x \) to find the corresponding \( y \). 1. Start with the equation: \[ 6x + y = 7 \] 2. Rearranging the equation to solve for \( y \): \[ y = 7 - 6x \] Now, we can choose a value for \( x \) to find \( y \). Let's choose \( x = 1 \): 3. Substitute \( x = 1 \) into the equation for \( y \): \[ y = 7 - 6(1) = 7 - 6 = 1 \] Thus, when \( x = 1 \), \( y = 1 \). Therefore, one ordered pair that is a solution to the equation is: \[ (x, y) = (1, 1) \] So, the final answer is: \[ (x, y) = (1, 1) \]