Select your answer \( \begin{array}{l}\text { Which of the following is equal to } \log (x y) ? \\ \begin{array}{l}\log (x)+\log (y) \\ \log (x)-\log (y)\end{array} \\ \begin{array}{l}\frac{\log (x)}{\log (y)} \\ \log (y)-\log (y)\end{array} \\ \text { (1 out of } 6)\end{array} \)
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The correct answer is \( \log (x) + \log (y) \). This property is based on the logarithmic identity that states the logarithm of a product is the sum of the logarithms of the individual factors. So, if you have two numbers \( x \) and \( y \), taking the logarithm of their product yields the sum of their logarithms. Fun fact: The roots of logarithmic properties can be traced back to the early 17th century when mathematicians like John Napier and Henry Briggs developed the concept of logarithms as a computational tool. Logarithms revolutionized calculations, making multiplication and division easier by transforming them into addition and subtraction!