Question 13 Find the domain of \( f(x)=\sqrt{x+1} \) Use two lower case o's for infinity. "oo" is how you type in infinity. Hint: You may find it helpful to graph the function on your graphing calculator. Question Help: \( \square \) Video \( \square \) Message instructor Submit Question

To find the domain of \( f(x) = \sqrt{x+1} \), you need to ensure that the expression inside the square root is non-negative. This means \( x + 1 \geq 0 \). Solving this inequality gives \( x \geq -1 \). Therefore, the domain of \( f \) is all real numbers \( x \) such that \( x \geq -1 \), or in interval notation, \( [-1, oo) \). If you're graphing this function, you'll notice that the curve starts from the point (-1, 0) and rises to the right without bound. This visual can help reinforce the understanding that the function is defined for all \( x \) values greater than or equal to -1, emphasizing that this is where the curve begins!