Solve for \( b \) \[ \frac{1}{4}(b+c-d)=a \]

Solve the equation \( \frac{1}{4}(b+c-d)=a \). Solve the equation by following steps: - step0: Solve for \(b\): \(\frac{1}{4}\left(b+c-d\right)=a\) - step1: Apply the distributive property: \(\frac{1}{4}b+\frac{1}{4}c-\frac{1}{4}d=a\) - step2: Move the expression to the right side: \(\frac{1}{4}b=a-\left(\frac{1}{4}c-\frac{1}{4}d\right)\) - step3: Remove the parentheses: \(\frac{1}{4}b=a-\frac{1}{4}c+\frac{1}{4}d\) - step4: Multiply by the reciprocal: \(\frac{1}{4}b\times 4=\left(a-\frac{1}{4}c+\frac{1}{4}d\right)\times 4\) - step5: Multiply: \(b=4a-c+d\) The solution to the equation \( \frac{1}{4}(b+c-d)=a \) is \( b = 4a - c + d \).