64.5 mL of ethanol (density \( =0.798 \frac{\mathrm{~g}}{\mathrm{~mL}} \) ). Round your answer to 3 significant digits. mass: \( \square \mathrm{g} \)

To calculate the mass of ethanol, you can use the formula: \[ \text{mass} = \text{volume} \times \text{density} \] Given: - Volume (\( V \)) = 64.5 mL - Density (\( \rho \)) = 0.798 g/mL \[ \text{mass} = 64.5 \, \text{mL} \times 0.798 \, \frac{\text{g}}{\text{mL}} = 51.471 \, \text{g} \] Rounding to three significant digits: \[ \text{mass} \approx 51.5 \, \text{g} \] **Mass: 51.5 g**