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What is the domain of \( g(x)=-\sqrt[3]{x}+5 \) ? (1 point) \( -\infty
Ask by Mcdonald Deleon. in the United States
Jan 23,2025

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The domain of \( g(x) = -\sqrt[3]{x} + 5 \) is all real numbers. **Answer:** \( -\infty < x < \infty \)

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Bonus Knowledge

The function \( g(x) = -\sqrt[3]{x} + 5 \) is defined for all real numbers, as the cube root function can accept any real input. This means that \( x \) can take on any value from negative infinity to positive infinity, making the domain \( -\infty < x < \infty \). Additionally, given that cube roots can yield both positive and negative outputs, this function also allows for all real values of \( g(x) \). Therefore, the range of \( g \) is also \( -\infty < y < \infty \), confirming the flexibility of the cube root in generating outputs.

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