Determine which point from the specified set satisfies the system of equations. \( y=\frac{-1}{3} x+3 \) \( y=\frac{-3}{4} x+8 \) \( \begin{array}{l}\text { Select Choice } \\ \text { Select Choice } \\ (9,0) \\ (12,-1) \\ (-8,14)\end{array} \)

To find which point satisfies the system of equations, we’ll substitute each point into both equations. **For the point (9, 0):** - Substitute into the first equation: \( y = \frac{-1}{3}(9) + 3 \) \ \( 0 = -3 + 3 \) \ \( 0 = 0 \) (True) - Substitute into the second equation: \( y = \frac{-3}{4}(9) + 8 \) \ \( 0 = -6.75 + 8 \) \ \( 0 ≠ 1.25 \) (False) **For the point (12, -1):** - Substitute into the first equation: \( y = \frac{-1}{3}(12) + 3 \) \ \( -1 = -4 + 3 \) \ \( -1 = -1 \) (True) - Substitute into the second equation: \( y = \frac{-3}{4}(12) + 8 \) \ \( -1 = -9 + 8 \) \ \( -1 = -1 \) (True) **For the point (-8, 14):** - Substitute into the first equation: \( y = \frac{-1}{3}(-8) + 3 \) \ \( 14 = \frac{8}{3} + 3 \) \ \( 14 ≠ \frac{8}{3} + 3 \) (False) Thus, the point that satisfies both equations is **(12, -1)**.