A lead sphere has a mass of \( 1.20 \times 10^{4} \mathrm{~g} \), and its volume is \( 1.14 \times 10^{3} \mathrm{~cm}^{3} \). Calculate its density. Round your answer to 3 significant digits.

To calculate the density of the lead sphere, use the formula: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \] **Given:** - Mass (\( m \)) = \( 1.20 \times 10^{4} \) g - Volume (\( V \)) = \( 1.14 \times 10^{3} \) cm³ **Calculation:** \[ \text{Density} = \frac{1.20 \times 10^{4}\, \text{g}}{1.14 \times 10^{3}\, \text{cm}^3} = \frac{12000\, \text{g}}{1140\, \text{cm}^3} \approx 10.5263\, \text{g/cm}^3 \] **Rounding to 3 Significant Digits:** \[ \text{Density} \approx 10.5\, \text{g/cm}^3 \] **Answer:** The sphere’s density is 10.5  g cm⁻³ when rounded to three significant digits.