Find \( f+g, f-g \), fg and \( \frac{f}{g} \). Determine the domain for each function. \[ f(x)=5 x+8, g(x)=x+6 \] \( (\mathrm{f}-\mathrm{g})(\mathrm{x})=4 \mathrm{x}+2 \) (Simplify your answer.) What is the domain of \( f-g \) ? A. The domain of \( f-g \) is \( (-\infty, \infty) \). (Type your answer in interval notation.) B. The domain of \( f-g \) is \( \{\quad \). (Use a comma to separate answers as neede C. The domain of \( f-g \) is \( \varnothing \). \[ (f g)(x)=5 x^{2}+38 x+48 \] (Simplify your answer.) What is the domain of fg ? A. The domain of \( f g \) is \( \square \) \} (Use a comma to separate answers as needed ) B. The domain of \( f g \) is \( \square \) (Type your answer in interval notation.) C. The domain of \( f g \) is \( \varnothing \)
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To find \( f + g, f - g, fg, \) and \( \frac{f}{g} \), let’s start with the functions given: 1. For \( (f + g)(x) \): \[ f + g = (5x + 8) + (x + 6) = 6x + 14 \] 2. For \( (f - g)(x) \): \[ f - g = (5x + 8) - (x + 6) = 5x + 8 - x - 6 = 4x + 2 \] 3. For \( (fg)(x) \): \[ fg = (5x + 8)(x + 6) = 5x^2 + 30x + 8x + 48 = 5x^2 + 38x + 48 \] 4. For \( \frac{f}{g} \): \[ \frac{f}{g} = \frac{5x + 8}{x + 6} \] Now let's determine the domains. ### Domain of \( f - g \): Since both \( f(x) \) and \( g(x) \) are polynomials, their difference \( f - g \) is also a polynomial, which is defined for all real numbers. Thus, the domain of \( f-g \) is \( (-\infty, \infty) \) (Answer A). ### Domain of \( fg \): Similarly, since \( fg \) is also a polynomial, it is defined for all real numbers. Thus, the domain of \( fg \) is \( (-\infty, \infty) \) (Answer B). So, the final answers for the domains are: - Domain of \( f-g \): \( (-\infty, \infty) \) - Domain of \( fg \): \( (-\infty, \infty) \)