Express \( e^{2}=7.389 \) in logarithmic form. \( \begin{array}{ll}\text { a. } \quad \log _{2} 7.389=e & \text { b. } \quad \log _{7.389}(e)=2 \\ \text { c. } \quad \ln 7.389=2 & \text { d. } \quad \ln 2=7.389\end{array} \)

To express \( e^{2} = 7.389 \) in logarithmic form, we can rewrite it as \( \ln(7.389) = 2 \). This corresponds to option **c**. So, the correct expression in logarithmic form is: \[ \ln(7.389) = 2 \] Hence, the answer is **c. \(\ln 7.389=2\)**. For extra clarity, remember that \( \ln(x) \) is the natural logarithm, meaning it's the logarithm with base \( e \)! This is particularly useful in calculus and any application involving continuous growth or decay, where \( e \) naturally arises.