Question Find the center and radius of the circle represented by the equation below. \[ (x+3)^{2}+(y+11)^{2}=196 \] Answer Attempt 1 out of 2 Center: \( (\square) \) (o) Watch Video Radius: Submit Answer
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The equation of a circle is generally given in the form \( (x-h)^{2}+(y-k)^{2}=r^{2} \), where \( (h, k) \) is the center and \( r \) is the radius. In your equation, you can clearly see \( (x+3) \) can be written as \( (x-(-3)) \) and \( (y+11) \) as \( (y-(-11)) \). This means the center is at \( (-3, -11) \). To find the radius, you take the square root of the right side of the equation. Since \( 196 \) is equal to \( r^{2} \), the radius \( r \) is \( \sqrt{196} \), which equals \( 14 \). So, the center is \( (-3, -11) \) and the radius is \( 14 \).