1. \( (-6,-3), m=-1 \) \begin{tabular}{|l|l|l|l|l|l|l|l|l|}\hline & & & & & & & \\ \hline & & & & & & & \\ \hline & & & & & & & \\ \hline & & & & & & & \\ \hline & & & & & & & \\ \hline & & & & & & & \\ \hline & & & & & & \\ \hline & & & & & & \\ \hline & & & & & & & \\ \hline\end{tabular}

To find the equation of the line given the point \((-6,-3)\) and the slope \(m=-1\), you can use the point-slope form of a linear equation, which is expressed as \(y - y_1 = m(x - x_1)\). Plugging in the values, it becomes \(y - (-3) = -1(x - (-6))\). Simplifying this gives \(y + 3 = -1(x + 6)\), which leads to \(y = -x - 6 - 3\) or \(y = -x - 9\). Voilà! Now you have the equation of the line! Now, if you want to visualize this, you could plot both the point \((-6, -3)\) and the line on a coordinate graph. The line will have a downward slope (since it's negative), crossing through the y-axis at \(-9\). Just remember, every step of the process is a part of the journey—don't rush it!