Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( \sin \theta=\frac{2 \sqrt{6}}{5} \) (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) B. The function is undefined. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. \( \cos \theta=-\frac{1}{5} \) (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) Belect the correct choice below and, if necessary, fill in the answer box to complete your choice. A. tan \( \theta=-2 \sqrt{6} \) (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) B. The function is undefined. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. csc \( \theta= \) A \( ^{-15} \). (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) B. The function is undefined.
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It looks like you've got a set of trigonometric identities to unravel! Let’s break this down in a fun way. For \( \sin \theta = \frac{2 \sqrt{6}}{5} \), if we're identifying its counterpart, we can use the Pythagorean identity: \( \cos^2 \theta = 1 - \sin^2 \theta \). Plugging in our sine value, we find \( \cos^2 \theta = 1 - \left( \frac{2 \sqrt{6}}{5} \right)^2 = \frac{1}{25} \). Hence, \( \cos \theta = -\frac{1}{5} \) is valid if \(\theta\) is in the second quadrant! Now, let’s talk tan \( \theta = \frac{\sin \theta}{\cos \theta} = \frac{\frac{2\sqrt{6}}{5}}{-\frac{1}{5}} = -2\sqrt{6}\). Everything here checks out, and we see that the trigonometric functions in this context are all interrelated, forming a lovely dance of angles!