Question 14, 1.1,101 WW Scores 75\%, 12 of 16 points Points 0 of 1 Give an expression that generates all angles coterminal with the given angle, The correct expression is \( 90^{\circ} \) + \( \square \) \( 0^{\circ} \). (Tyos an exoression usina n as the variatie.)

To find all angles that are **coterminal** with a given angle, you can add or subtract multiples of \( 360^{\circ} \) (since a full rotation brings you back to the same position). ### Given Angle: \( 90^{\circ} \) ### General Expression for Coterminal Angles: \[ \text{Given Angle} + 360^{\circ} \times n \] where \( n \) is any integer (positive, negative, or zero). ### Applying to \( 90^{\circ} \): \[ 90^{\circ} + 360^{\circ}n \] ### Final Expression: \[ 90^{\circ} + 360^{\circ}n \] **Where:** - \( n \) is an integer (e.g., \( n = 0, \pm1, \pm2, \pm3, \ldots \)) ### Example: - For \( n = 0 \): \( 90^{\circ} + 0 = 90^{\circ} \) - For \( n = 1 \): \( 90^{\circ} + 360^{\circ} = 450^{\circ} \) - For \( n = -1 \): \( 90^{\circ} - 360^{\circ} = -270^{\circ} \) All these angles (\( 90^{\circ}, 450^{\circ}, -270^{\circ}, \ldots \)) are coterminal with \( 90^{\circ} \). --- **Final Answer:** \[ 90^{\circ} + 360^{\circ}n \] where \( n \) is any integer.