- Simplipy \( \frac{6 \sqrt{2 x^{8}}-2 \sqrt{8 x^{8}}}{\sqrt{8 x^{8}}} \) without the use of a calu
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The Deep Dive
To simplify the expression \( \frac{6 \sqrt{2 x^{8}}-2 \sqrt{8 x^{8}}}{\sqrt{8 x^{8}}} \), let's break it down step by step. First, simplify each square root. We know that \( \sqrt{8 x^{8}} = \sqrt{8} \cdot \sqrt{x^{8}} = 2\sqrt{2} \cdot x^4 \). Similarly, \( \sqrt{2 x^{8}} = \sqrt{2} \cdot x^4 \). Now substituting back into the expression, we have: \[ \frac{6 \sqrt{2} x^4 - 2 (2\sqrt{2} x^4)}{2\sqrt{2} x^4} = \frac{6 \sqrt{2} x^4 - 4 \sqrt{2} x^4}{2\sqrt{2} x^4} \] Now combine like terms in the numerator: \[ \frac{(6\sqrt{2} - 4\sqrt{2}) x^4}{2\sqrt{2} x^4} = \frac{2\sqrt{2} x^4}{2\sqrt{2} x^4} = 1. \] So, the simplified expression is \( 1 \). There's a rich mathematical history to square roots and simplification! The concept of square roots dates back to ancient civilizations, including the Babylonians, who had methods for approximating them. The Pythagorean theorem, developed by the Greeks, relies heavily on understanding squares and roots, laying the foundation for algebra and geometry. When solving problems like this, a common mistake is to lose track of the variables or coefficients during simplification. Always double-check your work by ensuring each term is correctly combined or reduced. Also, keep an eye out for potential simplifications early on—clearly separating constants from variables can save time and prevent errors!