For what values of \( x \) is the following expression a real number? \( \sqrt{x-7} \)
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For the expression \( \sqrt{x-7} \) to be a real number, the value inside the square root must be non-negative. This means the inequality \( x - 7 \geq 0 \) must hold true. Solving this gives \( x \geq 7 \). Therefore, any value of \( x \) that is 7 or greater will result in a real number for the expression. Additionally, if you think about it, the square root function only produces real results when we have non-negative arguments, so grappling with this concept helps to firmly understand real-valued functions. Next time you're working with square roots, remember to check that the expression under the radical is positive or zero—it's a fun little safety check!