Solve the equation. Give a general formula for all the solutions. List six solutions. \( \sin \theta=-\frac{\sqrt{3}}{2} \) Identify the general formula for all the solutions to \( \sin \theta=-\frac{\sqrt{3}}{2} \) based on the smaller angle. \( \theta=\square, \mathrm{k} \) is an integer (Simplify your answer. Use angle measures greater than or equal to 0 and less than \( 2 \pi \). Type an exact answer, using \( \pi \) as needed. Use integers or fractions for any numbers in the expression. Type an expression using k as the variable.)
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To solve the equation \( \sin \theta = -\frac{\sqrt{3}}{2} \), we first identify the angles where the sine function takes on that value. The angle \( \theta \) that has a sine of \( -\frac{\sqrt{3}}{2} \) corresponds to the reference angle of \( \frac{\pi}{3} \) in the fourth and third quadrants. Therefore, the general formulas for the solutions are: \[ \theta = \frac{4\pi}{3} + 2k\pi \quad \text{and} \quad \theta = \frac{5\pi}{3} + 2k\pi \] where \( k \) is any integer. Now, let's list six specific solutions by substituting different integer values for \( k \): 1. For \( k = 0 \): \( \theta = \frac{4\pi}{3}, \frac{5\pi}{3} \) 2. For \( k = 1 \): \( \theta = \frac{4\pi}{3} + 2\pi = \frac{10\pi}{3}, \frac{5\pi}{3} + 2\pi = \frac{11\pi}{3} \) 3. For \( k = -1 \): \( \theta = \frac{4\pi}{3} - 2\pi = -\frac{2\pi}{3}, \frac{5\pi}{3} - 2\pi = -\frac{1\pi}{3} \) So, the six solutions we have identified are: \( \frac{4\pi}{3}, \frac{5\pi}{3}, \frac{10\pi}{3}, \frac{11\pi}{3}, -\frac{2\pi}{3}, -\frac{1\pi}{3} \)