Pregunta
7. Solve the equation \( \sqrt[3]{-2 x+5}=-3 \) for \( x \)
Ask by Mcguire Mann. in the United States
Jan 23,2025
Solución de tutoría real
Respuesta verificada por el tutor
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\( x = 16 \)
Solución
To solve the equation \( \sqrt[3]{-2x + 5} = -3 \) for \( x \), follow these steps:
1. **Eliminate the Cube Root:**
To remove the cube root, cube both sides of the equation:
\[
\left( \sqrt[3]{-2x + 5} \right)^3 = (-3)^3
\]
Simplifying both sides:
\[
-2x + 5 = -27
\]
2. **Isolate the Term with \( x \):**
Subtract 5 from both sides to isolate the term containing \( x \):
\[
-2x + 5 - 5 = -27 - 5
\]
Simplifying:
\[
-2x = -32
\]
3. **Solve for \( x \):**
Divide both sides by -2 to solve for \( x \):
\[
\frac{-2x}{-2} = \frac{-32}{-2}
\]
Simplifying:
\[
x = 16
\]
**Solution:**
\[
x = 16
\]
Revisado y aprobado por el equipo de tutoría de UpStudy
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Extra Insights
To solve the equation \( \sqrt[3]{-2 x+5}=-3 \), start by cubing both sides to eliminate the cube root. This gives you: \[ -2x + 5 = (-3)^3 \] Calculating the right side yields: \[ -2x + 5 = -27 \] Next, isolate \( -2x \) by subtracting 5 from both sides: \[ -2x = -27 - 5 \] This simplifies to: \[ -2x = -32 \] Now, divide both sides by -2 to solve for \( x \): \[ x = \frac{-32}{-2} = 16 \] Thus, the solution to the equation is \( x = 16 \).
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